8m^2-5m-29=0

Solution for 8m^2-5m-29=0 equation:

8m^2-5m-29=0

a = 8; b = -5; c = -29;
Δ = b2-4ac
Δ = -52-4·8·(-29)
Δ = 953
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{953}}{2*8}=\frac{5-\sqrt{953}}{16}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{953}}{2*8}=\frac{5+\sqrt{953}}{16}
$